90=5y^2

Solution for 90=5y^2 equation:

90=5y^2

We move all terms to the left:

90-(5y^2)=0

a = -5; b = 0; c = +90;
Δ = b2-4ac
Δ = 02-4·(-5)·90
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{2}}{2*-5}=\frac{0-30\sqrt{2}}{-10}
=-\frac{30\sqrt{2}}{-10}
=-\frac{3\sqrt{2}}{-1}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{2}}{2*-5}=\frac{0+30\sqrt{2}}{-10}
=\frac{30\sqrt{2}}{-10}
=\frac{3\sqrt{2}}{-1}
$